Write a function, which takes an array and two other paramters of int type, that

Question

Write a function, which takes an array and two other paramters of int type, that can move the previous (n-m) elements in a n-element array towards the end in sequence, and the last m elements move to the front in sequence.

Example:

How many numbers? 8

Input 8 numbers:

1 2 3 4 5 6 7 8

How many place you want to move? 4

Now, they are:

5 6 7 8 1 2 3 4

#include <stdio.h>
move(int array[20], int n, int m){
//write your code here
}
void main(){
   int number[20], n, m, i;
   printf("How many number?");
   scanf("%d", &n);
   printf("Input %d numbers: ", n);
   for (i = 0; i < n; i++){
       scanf("%d", &number[i]);
   }
   i = 0;
   printf("How many place you want to move?");
   scanf("%d", &m);
   move(number, n, m);
   printf("Now, they are: ");
   for (i = 0; i < n; i++){
       printf("%d ", number[i]);
   }
   getchar();
   getchar();
}

Explanation / Answer

#include <stdio.h>
move(int array[20], int n, int m)

{int i,j,k,new[20],result[20];
for( i=0;i<=m;i++)

new[i]=array[i];

for(i=0, j=m+1;i<=m,j<=n;i++,j++)

{result[i]=array[j];

if(i>m)

{for(i=m+1,k=0;i<=n,k<=m;i++,k++)

result[i]=new[k];

}

}

}

void main(){
   int number[20], n, m, i;
   printf("How many number?");
   scanf("%d", &n);
   printf("Input %d numbers: ", n);
   for (i = 0; i < n; i++){
       scanf("%d", &number[i]);
   }
   i = 0;
   printf("How many place you want to move?");
   scanf("%d", &m);
   move(number, n, m);
   printf("Now, they are: ");
   for (i = 0; i < n; i++){
       printf("%d ", number[i]);
   }
   getchar();
   getchar();
}

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