Write a bash script that prints to the standard output (screen/terminal) Number

Question

Write a bash script that prints to the standard output (screen/terminal) Number of arguments that were passed to it as positional parameters the first and third argument passed to it as one of the positional parameters the last arguments that was pass to it as the positional parameters or a message to the standard error that "No arguments has been received, " if it is a case For this problem, you may find useful to use bash variable $ {! name}, which means the value of the parameter whose name is $name This works when $name is either a named parameter or a number (denoting a positional parameter). Another way would be to use bash variable BASH ARGV or shift command.

Explanation / Answer

echo "Number of Arguments: $#"
echo "First and Third Arguments are: $1,$3"
echo "Last Argument is: ${@:${#@}}"

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