Assume the following values are stored at the indicated memory addresses and Fil
ID: 3834879 • Letter: A
Question
Explanation / Answer
Instruction Destination Value
addl %ecx, (%eax) %eax 0X100 + 0X1
subl %edx, 8(%eax) %eax 0X100+8 - 0X3
imull $16, (%eax, %edx,8) %eax 0X3 * 8 *16 => 0X3*128
incl 16(%eax) %eax (0X3 * 128) + 16
decl %ecx %ecx 0X1 - 1
subl %edx, %eax %eax [(0X3 * 128) + 16] - 0X3
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