Write a do-while loop that will iterate 1 time. You any not declare any variable
ID: 3835461 • Letter: W
Question
Write a do-while loop that will iterate 1 time. You any not declare any variables. J. Write an expression that determines the remainder when dividing z by x. Assume z and x are declared and initialized to a value. K. What is the C type of the following expression: size of (int)? Is it char, int, or double? L. Write an expression that shifts the value in variable x to the left by 3 bits. Assume x has been declared are assigned a value. M. Declare an array of 100 integers. N. Allocate an array of double values on the heap: the size of the array is held in a variable named size that is already declared. O. Given variables p and x, assign the address of x to p. You may assume the variables are declared and of the appropriate type. P. Assume that variable array is an integer array of length 101. Set the last element {greatest index) of array to 0. Q. Declare a variable and initialize it to hold the stringExplanation / Answer
Dear Student,
Here are the abswers...
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this loop print the statement one time only.
do
{
statement;
}while(0);
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Answer : J
int z = 10;
int x = 3;
int remainder = z%x;
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Answer No: K
sizeof(int); (for int type)
sizeof(float); (for float type)
sizeof(double); (for double type)
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Answer No: L
(3<<x) will shift x to 3 bits left.
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Answer No: M
int arr[100]; (array of 100 integer)
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Answer No: N
array = (double*)malloc(size * sizeof(double));
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Answer No: Q
int x, *p;
p = &x;
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Answer No: P
int array[101];
array[100] = 0; (set the last element to zero).
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Answer No: Q
char array[] = "Good luck";
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Kindly Check and Verify Thanks...!!!
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