Consider the following code. int x = 0; while (x < 5) { System.out.print(x + \"
ID: 3835854 • Letter: C
Question
Consider the following code.
int x = 0;
while (x < 5) {
System.out.print(x + " ");
x++;
}
System.out.println(x);
Suppose the initialization int x = 0; is replaced. What will be printed by each of the following replacements?
1. int x = 1;
2. int x = 2;
3. int x = 5;
4. int x = 6;
Ans Choices
A. 1 2 3 4 5
B. 6
C. 2 3 4 5
D. 5
Second Part
Consider the following code.
int x = 0;
while (x < 5) {
System.out.print(x + " ");
x++;
}
System.out.println(x);
Suppose the test x < 5 is replaced. What will be printed for each of the following replacements?
1. x < 0
2.x >= 0
3.x < 3
4.x <= 3
Ans Choices:
A. 0
B. 0 1 2 3
C.results in an infinite loop
D.0 1 2 3 4
Explanation / Answer
Answers for the first question are as follows.
When int x=0 is replaced with int x = 1 then the output is option (A) 1 2 3 4 5.
When int x=0 is replaced with int x = 2 then the output is option (C) 2 3 4 5
When int x=0 is replaced with int x = 5 then the output is option (D) 5
When int x=0 is replaced with int x = 6 then the output is option (B) 6
Answers for the second question are as follows.
When x < 5 is replaced with x < 0 then the output is option (A) 0
When x < 5 is replaced with x >= 0 then the output is option (C) results in an infinite loop
When x < 5 is replaced with x < 3 then the output is option (B) 0 1 2 3
When x < 5 is replaced with x <= 3 then the output is option (D) 0 1 2 3 4
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