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Consider the following code. int x = 0; while (x < 5) { System.out.print(x + \"

ID: 3835854 • Letter: C

Question

Consider the following code.

  

   int x = 0;

   while (x < 5) {

      System.out.print(x + " ");

      x++;

   }

   System.out.println(x);

  

Suppose the initialization int x = 0; is replaced. What will be printed by each of the following replacements?

1. int x = 1;

2. int x = 2;

3. int x = 5;

4. int x = 6;

Ans Choices

A. 1 2 3 4 5

B. 6

C. 2 3 4 5

D. 5

Second Part

Consider the following code.

  

   int x = 0;

   while (x < 5) {

      System.out.print(x + " ");

      x++;

   }

   System.out.println(x);

  

Suppose the test x < 5 is replaced. What will be printed for each of the following replacements?

1. x < 0

2.x >= 0

3.x < 3

4.x <= 3

Ans Choices:

A. 0   

B. 0 1 2 3   

C.results in an infinite loop

D.0 1 2 3 4

Explanation / Answer

Answers for the first question are as follows.

When int x=0 is replaced with int x = 1 then the output is option (A) 1 2 3 4 5.

When int x=0 is replaced with int x = 2 then the output is option (C) 2 3 4 5

When int x=0 is replaced with int x = 5 then the output is option (D) 5

When int x=0 is replaced with int x = 6 then the output is option (B) 6

Answers for the second question are as follows.

When x < 5 is replaced with x < 0 then the output is option (A) 0

When x < 5 is replaced with x >= 0 then the output is option (C) results in an infinite loop

When x < 5 is replaced with x < 3 then the output is option (B) 0 1 2 3

When x < 5 is replaced with x <= 3 then the output is option (D) 0 1 2 3 4

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