This is an Introductory C++ course and I would like to write this program withou

Question

This is an Introductory C++ course and I would like to write this program without using please. Write a C++ program that reads in and prints a text, line by line, and calls a series of functions. The main program calls a function diffwords() to count the number of different words in the entire text (ignoring case). It also calls a function wordcount() to count the number of times each word appears in the text. Then it calls a function printcount() to print a list of all the words in the text, together with the count of the number of times they appear. For example, if a word occurs twice in the text, it appears only once on the list, with a count of 2. Print the list of words in alphabetical order. Use other functions wherever appropriate. For example, suppose the text is this: The elephant ate the banana and the giraffe ate the banana. The function diffwords() produces a count of 6 ("the", "elephant", "ate", "banana", and "giraffe"); wordcount() produces this list: and 1 ate 2 banana 2 elephant 1 giraffe 1 the 4

Explanation / Answer

#include<iostream.h>
#include<string>
#include<sstream>
#include<vector>
#include<algorithm>

using namespace std;

struct item {
    string data;
    int count;
};

void diffwords(stringstream stream){
    int count;
    vector<string> list;
    string word;
    count = 0;
    while (getline(stream, word, ' ')) { //Accessing each word
        if (std::find(list.begin(),list.end(), word) != list.end())
           continue;
        count++;
        list.push_back(word);
    }
    cout << count << "(";
    for (int i = 0; i<list.size(); i++){
        if (i < list.size -1)
           cout << """ << list.at(i) << """, ", ";
        else
           cout << """ << list.at(i) << """, ")");
    }   
}

void wordcount(stringstream stream){
    int count;
    vector<string> list
    vector<item> list1;
    item temp;
    string word;
   
    while (getline(stream, word, ' ')) {
        if (std::find(list.begin(),list.end(), word) != list.end()){
           for (int i =0; i<list1.size(); i++){
               if (list1.at(i).data == word)
                  list1.at(i).count++;
           }
           continue;   // if the word is present we don't need to enter in the list
        }
        list.push_back(word);
        temp.data = word;
        temp.count = 1;
        list1.push_back(temp);       
       
    }
    for (int i = 0; i<list1.size()-1; i++){   // Sorting the words
        for (int j = 0; j < list1.size()-i-1; j++){
            if (list1.at(j).data > list1.at(j+1).data){
                temp = list1.at(j);
                list1.at(j) = list1.at(j+1);
                list1.at(j+1) = temp;
            }
        }
    }

    for (int i = 0; i<list1.size(); i++){
        cout << list1.at(i).data << " " << list.at(i).count << " ";
    }   
}

int main(){
    string data;
    cout << "Enter some text" << endl;
    getline(cin, data);
    stringstream stream(data);
    diffwords(stream);
    wordcount(stream);
}

// Output format of printcount function is not specified also its description looks very much similar to wordcount

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.