This is a group assignment. Please work with your Project Group to answer the fo
ID: 3852775 • Letter: T
Question
This is a group assignment. Please work with your Project Group to answer the following questions. You may enter your answers directly into this document. Select one member of your group to submit the group's completed assignment as a PDF document via Canvas before the due date/time. Remember to enter the Project Group number and Submitter's name above. A hard disk is organized with fixed sectors with 512 bytes per sector, 96 sectors per track, 110 tracks per surface, and 8 usable surfaces. a) Calculate how much disk space (in sectors, tracks, and surfaces) will be required to store 300,000 120-byte logical records. Ignore any file header record(s) and track indexes, and assume that records cannot span two sectors. b) Assume that the disk rotates at 7200 rpm. A processor reads one sector from the disk using interrupt-driven I/O, with one interrupt per byte. If it takes 2.5 mu s to process each interrupt, what percentage of the time will the processor spend handling I/O? (Disregard seek time.) c) Repeat the calculation of part (b) using DMA, and assume one interrupt per sector.Explanation / Answer
answer :
a) part
120 byte - logical records and per sector stores 512 bytes then
each sector can store maximum = 120 * 4 = 480 bytes (means each sector can store 4 logical records )
then
no. of sectors required to store 300,000 and each sector can store only 4 logical record = 300000/4
we get 75,000sectors
no of tracks required for 75,000 sectors and there are 96 sectors per track = 75000/96 = 782 tracks
no. of surfaces required for 782 tracks and there are 110 tracks per surface = 782 / 110= 8 surfaces
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