Suppose that plaintext message units are trigraphs in the 32 letter alphabet, a-
ID: 3857037 • Letter: S
Question
Suppose that plaintext message units are trigraphs in the 32 letter alphabet, a-z corresponds to 0-25, blank=26, ?=27, !=28, .=29, ‘=30, $= 31 . You receive the sequence of Ciphertext message units 152472, 116116, 68546, 165420, 168261. The public key is the sequence {24038, 29756, 34172, 34286, 38334, 1824, 18255, 19723, 143, 17146, 35366, 11204, 32395, 12958, 6479} , and the secret key is b = 30966, m = 47107. Decipher the message.
5. Suppose that plaintext message units are trigraphs in the 32-letter h A-.Z corresponding to 0-25, blank-26, ?-27,-28, alphabet wit .=29,'=30, $=31. You receive the sequence of ciphertext message units 152472, 116116, 68546, 165420, 168261. The public key is the sequence (24038, 29756, 34172, 34286, 38334, 1824, 18255, 19723, 143, 17146, 35366, 11204, 32395, 12958, 6479), and the secret key is b 30966, m = 47107-Decipher the message.Explanation / Answer
Decrypting: [152472, 116116, 68546, 165420, 168261] Using public key: [24038, 29756, 34172, 34286, 38334, 1824, 18255, 19723, 143, 17146, 35366, 11204, 32395, 12958, 6479] b = 30966 m = 47107 Calculated key sequence: [23001, 11376, 5611, 2710, 1351, 691, 330, 163, 80, 39, 20, 9, 5, 2, 1] Calculated msg segments: [7556, 17853, 1123, 27647, 6177] Binary segments found using calculated key and msg segments as the 'V' in the knapsack problem: Bin Dec Let 00101 5 f 01110 14 o 10001 17 r 01100 12 m 10100 20 u 01011 11 l 00000 0 a 11010 26 10010 18 s 10011 19 t 01110 14 o 01011 11 l 00100 4 e 01101 13 n 11100 28 ! Decrypted Message: formula stolen!
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