Genotypes of leopard frogs from a population in central Kansas were determined f

Question

Genotypes of leopard frogs from a population in central Kansas were determined for a locus (M) that encodes the enzyme malate dehydrogenase. The following #'s of genotypes were observed: Total sample =107

a. Calculate the allelic frequencies for this population.

Alleles = M1 and M2

For M1: I did ((2*20) +45)/(107*2) = 0.3971 -->1 sig fig = 0.4

For M2: ((2*42) +45)/(107*2) = 0.6028 -->2 sig fig = 0.60

This makes sense to me but I'm not sure if this is correct??

Explanation / Answer

Yeah, Your calculation is right. Please find the detail calculation with explanation.

Two alleles are possible, M1 or M2, that can combine to give the following genotypes M1M1, M1M2, M2M2 for a locus that encodes the enzyme malate dehydrogenase.
Therefore, this entire population of leopard frogs consists of 214 i.e 107 X 2 alleles at the malate dehydrogenase enzyme locus. To deter mine the allelic frequencies, simply count the number of M 1or M2 alleles and divide by the total number of alleles.

So the allelic frequency for the M1 allele will be:

f(M1) = [(2 x 20) +45 ]/214 = 0.3971

and the frequency for the M2 allele will be:

f(M2) = [(2 x 42) + 45]/214 = 0.6028

By convention one of the alleles is given the designation P and the other q. Thus for the data we presented above, p=0.3971 and q=0.6028. Because we are analyzing all the alleles, the frequencies should sum to 1.0 and p + q = 1.

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