Example 1: Assume that part X routing is Machine A, then B, then C; 50,000 parts
ID: 386034 • Letter: E
Question
Example 1: Assume that part X routing is Machine A, then B, then C; 50,000 parts are to be produced per year. In addition, part Y routing is Machine B, then C, then A; 100,000 parts are to be produced per year. Given the following information, how many machines A, B and C is needed to produce parts X and Y? Part X standard time Part Y standard time Part X scrap estimate Part Y scrap estimate Historical efficiency Equipment availability Machine A 0.20 hr 0.05 hr 5% 4% 95% 2000 hrs/yr Machine B 0.05 hr 0.10 hr 2% 3% 90% 2000 hrs/yr Machine C 0.10 hr 0.08 hr 0% 0% 100% 1800hrs/yrExplanation / Answer
Steps followed are as follows:
Determine number of input units required at the machines considering scrap percentage.
Input units required = (1 + scrap rate) x output required.
Calculate total hour required to produce above units by multiplying units required to process with standard time
Product
Machine sequence
X
A
B
C
Output
Scrap rate
5%
2%
0%
Quantities
(1+0.05)*51000
= 53550
(1+00.2)*50000
= 51000
(1+0)*50000
= 50000
50,000
Standard time
0.2
0.05
0.1
Total Hours required
0.2*53550
= 10710
2550
5000
Product
Machine sequence
Y
B
C
A
Output
Scrap rate
3%
0%
4%
Quantities
107120
104000
104000
100,000
Standard time
0.1
0.08
0.05
Total Hours required
10712
8320
5200
Determine total load in hours required at each machine to produce X and Y.
Determine actual hours available per year by multiplying efficiency and design available time/hr.
Determine number of machines required by dividing total load by actual hours available.
Machine
A
B
C
Load (hrs) from X
10710
2550
5000
Load (hrs) from Y
5200
10712
8320
Total Load (hrs.)
15910
13262
13320
Available time/year
2000
2000
1800
Efficiency
95%
90%
100%
Actual hours Available
1900
1800
1800
Number of Machines required
8.4
7.4
7.4
Actual No. of Machines required
9
8
8
Requirements are as follows:
M/c A = 9, M/c B = 8, and M/c = 8
Product
Machine sequence
X
A
B
C
Output
Scrap rate
5%
2%
0%
Quantities
(1+0.05)*51000
= 53550
(1+00.2)*50000
= 51000
(1+0)*50000
= 50000
50,000
Standard time
0.2
0.05
0.1
Total Hours required
0.2*53550
= 10710
2550
5000
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