THIS IS A Beginner Course_Introduction to JAVA Note: You Must use API only(Metho

Question

THIS IS A Beginner Course_Introduction to JAVA

Note: You Must use API only(Method on String)

Given a string, print true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive).

Sample 1

equalIsNot("This is not") false

Sample 2

equalIsNot("This is notnot") true

Sample 3

equalIsNot("noisxxnotyynotxisi") true

Also, Given a string, replace all the white spaces with “V_V” and print out the new string.

Sample 1

replaceWhiteSpace(“How are you?) “HowV_VareV_Vyou?”

Sample 2

replaceWhiteSpace(“I am good?) “IV_VamV_Vgood?"

PLEASE Do NOT use advanced high level syntax.

PLEASE Do NOT use advanced libraries beyond a beginner level.

Explanation / Answer

code:

public static int count(String str, String substr)
{
int cnt = 0;
int id = 0;

while ((id = string.indexOf(substr, id)) != -1)
{
id++;
cnt++;
}

return cnt;
}
public static bool equalIsNot(String str)
{
if(count(str,"is")==count(str,"not")
return true;
else
return false;
  
}

public static String replaceWhiteSpace(String str)
{
return str.replaceAll(" ",“V_V”);
}

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