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How many rows will be inserted into the tab1 table after the following PL/SQL bl

ID: 3866795 • Letter: H

Question

How many rows will be inserted into the tab1 table after the following PL/SQL block has been executed successfully (no runtime error)?

DECLARE

     v_count    NUMBER := 1;

     v_1        NUMBER := 1;

BEGIN

     DELETE FROM tab1;

     COMMIT;

     FOR i IN REVERSE 6..11 LOOP

           INSERT INTO tab1 VALUES (i, i*2, i+3);

    END LOOP;

          

     SELECT     COUNT(*)

    INTO       v_count

     FROM       tab1;

             

     FOR i IN 3..v_count + 11 LOOP

           INSERT INTO tab1 VALUES (i, i+10, i+20);

     END LOOP;

    INSERT INTO tab1 VALUES (99, 205, 306);

  

    SELECT     COUNT(*)

    INTO       v_1

     FROM       tab1;

     

   WHILE v_1 >= 7 LOOP

           IF v_1 = 10 OR v_1 = 25 OR v_1 = 35 OR v_1 = 45 THEN

                INSERT INTO tab1 VALUES (v_1*20, v_1*30, v_1*40);

           ELSE

                v_1 := v_1 - 1;

           END IF;

           v_1 := v_1 - 2;

    END LOOP;

     FOR i IN 2..48 LOOP

           IF i = 4 OR i = 16 OR i= 32 OR i = 48 THEN

                INSERT INTO tab1 VALUES (i*20, i*30, i*40);

           END IF;

           INSERT INTO tab1 VALUES (i*21, i*31, i*41);

      END LOOP;

     INSERT INTO tab1 VALUES (616, 222, 243);

     INSERT INTO tab1 VALUES (77, 88, 99);

     INSERT INTO tab1 VALUES (77, 88, 55);

   INSERT INTO tab1 VALUES (66, 88, 99);

     INSERT INTO tab1 VALUES (66, 88, 91);

     COMMIT;

END;

A.        75

B.        76

C.        77

D.        78

E.         79

F          80

Explanation / Answer

1. Initially all the rows from table tab_1 is deleted.

2. First for loop (FOR i IN REVERSE 6..11 LOOP) iterates for 6 times (11, 10, 9, 7, 8, 6) and inserts 6 records into table tab1.

3. Second for loop (FOR i IN 3..v_count + 11 LOOP) iterates from 3 to 17 (6 + 11) and inserts 15 records into table tab1.

4. As of now, total records in table tab1 is 21 records.

5. A single insert statement inserts another record into table. (Total records as of now: 22)

6. Value of v_1 will be 22

7. While loop gets iterated for 6 times. Values of v_1 at each iteration
  
   Iteration 1: v_1 = 22
   Iteration 2: v_1 = 19
   Iteration 3: v_1 = 16
   Iteration 4: v_1 = 13
   Iteration 5: v_1 = 10
   Iteration 6: v_1 = 8

When the value of v_1 is 10 a new record is inserted into table. (Total records as of now: 23)

8. Last for loop iterates from 2 to 48 and inserts 51 records into table tab1 and four extra records when the value of i = 4 OR i = 16 OR i= 32 OR i = 48.

9. As of now, total records in table tab1 is 74 (23 + 51) records.

10. Five individual insert statements inserts 5 more records in to table tab1.

11. As a total, 79 rows will be inserted into the tab1 table after the following PL/SQL block has been executed successfully.


Hence correct option is (E - 79)

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