Needs to be in c++ format! Problem 4: 1)19 ten. 2)-7/6 ten. 3)0.3 ten. 4)63.50 t

Question

Needs to be in c++ format!

Problem 4:

1)19 ten.

2)-7/6 ten.

3)0.3 ten.

4)63.50 ten.

Problem 6 (20 points) Write a C/C++ program to extract the sign bit, exponent field, and the fraction field of a 32-bit hexadecimal number (in the IEEE 754 standard) and then compute the corresponding floating- point in decimal using formula (-I)'g x(1+fraction×2-23)x2ep -127)(You can ignore special cases including 0). Print each field as unsigned hexadecimal (%X) and the decimal value in scientific notation ("%E"). Then apply your program on the four representations from Problem 4 above (single precision only) and include your running results. You need to attach a copy of your program or submit it electronically. Program hint: You may find the following union structure convenient. union ieee754_hex { unsigned int hex; struct unsigned int fraction:23; unsigned int exponent:8; unsigned int s:1;

Explanation / Answer

#include<iostream>

union ieee754

{

unsigned int hex;

struct mem

{

unsigned int fraction:23;

unsigned int exponent:8

unsigned int sign:1;

};

};

int main()

{

int dec;

union ieee754 u1;

struct mem m1;

printf("please enter a hexadecimal no of 32 bit in hexadecimal format");

scanf("%x",&u1.hex);

printf("the fraction bit is %X decimal value of scientific notation %E",u1.m1.fraction,u1.m1.fraction);

printf("the exponent bit is %Xdecimal value of scientific notation %E",u1.m1.exponent,u1.m1.exponent);

printf("the sign bit is %X decimal value of scientific notation is %E",u1.m1.sign,u1.m1.sign);

dec=((-1)^(u1.m1.sign))*((1+u1.m1.fraction)*(2^(-23)))*((2^(u1.m1.exponent-127)));

return 0;

}

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