Consider the following C code: void greet {char *arg) { char buffer [16]: printf

Question

Consider the following C code: void greet {char *arg) { char buffer [16]: printf("I am the Senate. What is your name? "): scanf("%s", buffer): printf("It's treason then, %s ", buffer): } int main(int arge char *argv[]) { char beg [6] = 'Kenobi': char end [9] = 'maybe not?': strncat(beg, end, 5): greet(argv[1]): return 0: } What is the line number that has a memory vulnerability and what is this vulnerability called? Just before the program executes line 4, the registers are: %esp: 0xBFFFFB20 %ebp: 0xBFFFFB48 Given this information, describe in detail how an attacker would take advantage of the vulnerability. Also make sure to include the address that the attacker needs to over-write. (Maximum 5 sentences) What would you change to fix the problem in part 1? Given the code as is, would stack canaries prevent exploitation of this vulnerability? Why or why not?

Explanation / Answer

Computer security, also known as cyber security or IT security, is the protection of computer systems from the theft or damage to their hardware, software or information, as well as from disruption or misdirection of the services they provide.[1]

Cyber security includes controlling physical access to the hardware, as well as protecting against harm that may come via network access, data and code injection.[2] Also, due to malpractice by operators, whether intentional, accidental, IT security is susceptible to being tricked into deviating from secure procedures through various methods.[3]

The field is of growing importance due to the increasing reliance on computer systems and the Internet,[4] wireless networks such as Bluetooth and Wi-Fi, and the growth of "smart" devices, including smartphones, televisions and tiny devices as part of the Internet of Things.

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