QUESTION 26 Given the following equation for an FM signal, select the correct in

Question

QUESTION 26

Given the following equation for an FM signal, select the correct information below:

sFM(t) =3cos[(2280khz*t)+3sin(24000Hz*t)], kVCO=2000(Hz/v)

a. FM Index, =9, Message Amplitude, Am=3v

b. FM Index, =3, Message Amplitude, Am=6v

c. FM Index, =3, Message Amplitude, Am=3v

d. FM Index, =9, Message Amplitude, Am=6v

10 points   

QUESTION 27

Determine your FM bandwidth given the following: FM Index =5, frequency of your message is fm-4000Hz.

a. 4 kHz

b. 12 kHz

c. 24 kHz

d. 48 kHz

10 points   

QUESTION 28

Given the following equation for an PM signal, select the correct information below:           

sPM(t) =3cos[(2300MHz*t+5cos(24kHz*t)], kP=0.3

a. PM Index, µp=5, Message Amplitude, Am=16.67v

b. PM Index, µp=6, Message Amplitude, Am=16.67v

c. PM Index, µp=3, Message Amplitude, Am=6v

d. PM Index, µp=6, Message Amplitude, Am=5v

10 points   

QUESTION 29

With PM, the message amplitude and frequency are directly related to bandwidth.

True

False

10 points   

QUESTION 30

When frequency division multiplexing (FDM) is used, guard channels are NOT required in-between frequency channels.

True

False

a. FM Index, =9, Message Amplitude, Am=3v

b. FM Index, =3, Message Amplitude, Am=6v

c. FM Index, =3, Message Amplitude, Am=3v

d. FM Index, =9, Message Amplitude, Am=6v

Explanation / Answer

26 c ( v(t)= Ac cos(2fct+ kfsin2fmt) where Ac is message amplitude and kf is Modulation index)

27 d ( Band width = 2 * 4000 * (5 + 1))

28 b

29 True

30 False

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