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A solution to your program declares 13 variables. Write a solution that has a fe

ID: 3888578 • Letter: A

Question

A solution to your program declares 13 variables. Write a solution that has a few declarations as possible.

// ConsoleApplication1.cpp : Defines the entry point for the console

application.

//

#include <iomanip>

#include <iostream>

#include <random>

#include <string>

using namespace std;

int main()

{

default_random_engine e;

uniform_int_distribution<int> u(1000, 9999);

int number = u(e);

int digit1 = number % 10;

int number1 = number / 10;

int reversed = digit1;

int sum = digit1;

int digit2 = number1 % 10;

int number2 = number1 / 10;

reversed = 10 * reversed + digit2;

sum = sum + digit2;

int digit3 = number2 % 10;

int number3 = number2 / 10;

reversed = 10 * reversed + digit3;

sum = sum + digit3;

int digit4 = number3 % 10;

int number4 = number3 / 10;

reversed = 10 * reversed + digit4;

sum = sum + digit4;

cout << "The original number - " << number << endl;

cout << "with digits reversed - " << reversed << endl;

cout << "and the digits' sum is " << setw(4) << sum << endl;

system("pause");

return 0;

}

Explanation / Answer

You can reduce the no of variables by reusing the already declared variables.

default_random_engine e; //one variable

uniform_int_distribution<int> u(1000, 9999); //2nd variable

int number = u(e); //number is used as a temporary variable on which the operations are performed 3rd variable

int digit= number % 10; //to get the remainder 4th variable

number = number / 10; //instead of declaring a new variable number can be used

int reversed = digit; //used to store reverse of number 5th variable

int sum = digit; //used to store the sum of the numbres 6th variable

digit = number % 10; //instaed of the new integer as digit1 is not used any where in the program it can be used

number = number / 10; //instead of a new variable number can be updated

reversed = 10 * reversed + digit;

sum = sum + digit;

digit = number % 10;

number = number / 10;

reversed = 10 * reversed + digit;

sum = sum + digit;

digit = number % 10;

number = number / 10;

reversed = 10 * reversed + digit;

sum = sum + digit;

cout << "The original number - " << u(e) << endl; //the original number is in u(e) it is not in variable number because it is modified

cout << "with digits reversed - " << reversed << endl;

cout << "and the digits' sum is " << setw(4) << sum << endl;

system("pause");

return 0;

So 6 variables are used.

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