Please USE only PYTHON to solve the following problem and be sure to follow all

Question

Please USE only PYTHON to solve the following problem and be sure to follow all instructions carefully. Thank you.

The template as provided below is for your reference:

The following info is for your reference only. No need to solve the problem below. Please read all instructions carefully. Thank you.

NOTE: Please make sure the output you get matches the example. The "+" sign needs to be included for the 19 (last line). Thanks

price_chart (age, num_pets): This function creates a multi-line string showing one-way prices for rush hour and non-rush hour in a chart-like fashion. The columns are labeled Stops (from 1 through "19+"), Rush pricing (for that age and number of pets), and off-peak for non-rush hour pricing (for that age and number of pets). There are always 20 lines (header line and 19 stop-prices), with a single tab between items on a line. All prices should be floats (we see S1.0 instead of S1). Below are some examples; use the tester examples for further guidance on exact formatting. age and num_pets are both non-negative int values. Loops are recommended for your solution but are not required. This function returns a string, but printing it makes it easier to see the purpose; thus we mostly call print(price_chart()) below . >>>price chart (18,) »>print (price chart(70,0)) Stops Rush Off-peak $4.0 $8.5 2 $4.0 $1.0 3 $4.0 $1.5 4 $4.0 $2.e t$8.25 13 $12.0 $8.5in14t$12.t$8.75 15 $ 12.t$9.8 16t$12. $9.25 17 $12.8 $9.5 18) t$12.t$9.75 19+1t$12.8 $10, ' >>>print(price chart (1e,)) Stops Rush Off-peak $4.0 $2.5 6 $4.0 $2.75 7 $4.0 $3.e 8 $4.0 $3.25 9 $4.0 $3.5 10 $4.0 $3.75 11 $4.0 $4.6e 12 $4.0 $4.0 13 $4.0 $4.6e 14 $4.0 $4.60 15 $4.0 $4.e 16 $4. $4.6e 17 $4.0 $4.6e 18 $4.0 $4.6e 19 $4.0 $4.6e $8.0 $1.0 2 $8.0 $2.e 3 $8.0 $3.0 4 $8.0 $4.6e $8.0 $5.0 6 $8.e $5.5 7 $8.e $6.0 8 $8.0 $6.5 10 $8.0 $7.5 11 $12.0 $8. 12 $12.0 $8.25 13 $12.0 $8.5 14 $12.0 $8.75 15 $12.0 $9.e 16 $12.8 $9.25 17 $12.0 $9.5 18 $12.0 $9.75 19+ $12.0 $18.0 >> print (price_chart(2,0)) Stops Rush off-peak 1 $8.0 $e.8 2 $0.0 $0.e 4$0.9$0.0 5 $0.0 $0.e 6 7 $0.0 $0.8 >>> print (price_chart (20,5)) Stops Rush Off-peak 1$13.0 $6.0 2 $13.0 $7.8 3 $13.0 $8.0 4 $13.0 $9.e 5 $13.0 $10.0 6 $13.0 $10.5 7 $13.0 $11.0 8 $13.0 $11.5 9 $13.0 $12.e 10 $13.0 $12.5 11 $17.9 $13.0 12 17.0 $13.25 13 $17.0 $13.5 14 17.0 $13.75 15 $17.0 $14.0 16 $17.8 $14.25 17 $17.0 $14.5 18 $17.0 $14.75 19+ $17.0 $15.0 9 $0.0 $0.e 10 $0.0 $0.e 11 $0.0 $0.e 12 $0.0 $0.e 13 $0.0 $0.6e 14 $0.0 $0.0 16 $0.0 $8.0 17 $0.9 $0.0 18 $e.0 $0.e 19 $0.0 $0.6e

Explanation / Answer

def check_rush_hour(day,hour,minute):
    list = ["Monday","Tuesday","Wednesday","Thursday","Friday"]
    if day in list:
       if hour >= 0 and hour <= 23:
         if minute >= 0 and minute <= 59:
           if hour > 5 and hour < 9:
              return True
           if hour == 5:
              if minute >= 30:
                 return True
           if hour == 9:
              if minute < 30:
                 return True
           if hour > 15 and hour < 19:
              return True
           return False
         else:
           print("Invalid data")
           return False
       else:
         print ("Invalid data");
         return False;      
    else:
      return False

def simple_fare(num_stops):
    if num_stops <= 5:
       return num_stops
    else:
       if num_stops <= 11:
          return 5 + (num_stops - 5) * 0.5
       else:
          if num_stops <= 19:
            return 5 + 3.0 + (num_stops - 11) * 0.25
          else:
            return 10

def fare(num_stops, age, is_rush_hour, want_return_fare, num_pets):
   
    if age < 5:
       return 0
    if age >= 65:
       price = num_pets * 1
       if is_rush_hour:
          price = 4
       else:
          price = (price + simple_fare(num_stops))/2
          if price > 4:
             price = 4
       if want_return_fare:
             price = price + price

    if age > 5 and age < 65:
       price = num_pets * 1
       if is_rush_hour:
          if num_stops <= 10:
             price = price + 8
          else:
             price = price + 12
       else:
          price = price + simple_fare(num_stops)
       if want_return_fare:
             price = price + price
    return price

def price_chart(age, num_pets):
    print("Stops "," Rush "," Off-peak ")
    for i in range(19):
        rush_fare = float(fare(i+1, age, True, False, num_pets))
        fare_off = float(simple_fare(i+1)) + num_pets
        if i+1 == 19:
            print("19+", "      $"+str(rush_fare), "       $"+str(fare_off))
        else:
           
            print(i+1, "      $" +str(rush_fare), "       $"+str(fare_off))

print (check_rush_hour("Monday", 6,0))
print (check_rush_hour("Tuesday", 16,15))
print (check_rush_hour("Wednesday", 9,30))
print (check_rush_hour("Friday", 5,30))
print (check_rush_hour("Saturday", 5,30))
print(simple_fare(1))
print(simple_fare(5))
print(simple_fare(6))
print(simple_fare(11))
print(simple_fare(12))
print(simple_fare(30))

print("-------------------")

print(fare(30,3,False,False,0))
print(fare(1,20,False,False,15))
print(fare(5,20,False,False,0))
print(fare(5,20,False,True,0))
print(fare(6,20,False,True,0))
print(fare(5,20,True,False,0))
print(fare(11,20,True,False,0))
print(fare(7,65,False,False,0))
print(fare(7,65,False,True,0))
print(fare(100,65,True,False,0))
print(fare(14,35,False,True,3))
print(fare(14,50,True,False,100))
price_chart(20,5)

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