%3Cp%3E%3Cimg%20class%3D%22user-upload%22%20src%3D%0A%22http%3A%2F%2Fmedia.chegg
ID: 3894489 • Letter: #
Question
%3Cp%3E%3Cimg%20class%3D%22user-upload%22%20src%3D%0A%22http%3A%2F%2Fmedia.cheggcdn.com%2Fmedia%252Fffb%252Fffb7d5c3-e414-46fd-8ed3-15a8cdac85fb%252FphpxrouEL.png%22%0Aheight%3D%22778%22%20width%3D%22581%22%20%2F%3E%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3E%3Cbr%20%2F%3E%3C%2Fp%3E%0A%3Cp%3EI'm%20not%20sure%20how%20to%20solve%20for%20this.%20%20I%20know%20the%20answer%20is%0A45.6m%2Fs%20but%20don't%20know%20how%20they%20got%20that%20answer.%3C%2Fp%3E%0AExplanation / Answer
take upward and right as positive
for y direction:
s=ut+0.5at^2
-20+10=v sin 30*t+0.5 *-9.8*t^2;
=>-10=v sin 30*t-4.9*t^2
for x direction:
a=0;
200=v cos 30* t
=>v*t=200/0.866=230.94;
substitute back
-10=230.94*0.5-4.9*t^2
=>4.9 t^2=125.4
=>t^2=25.6
=>t=5.06sec
v*t=230.94
=>v=45.63 m/sec
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