Suppose the probe, which has a mass of 474kg is traveling at an initial speed of

Question

Suppose the probe, which has a mass of 474kg is traveling at an initial speed of 275m/s. No forces act on it except the 5.60x10^-2 N thrust of its engine. The external force is directed parallel to the displacement s, which has a manitude of 2.42x10^9. determine the final speed of the probe, assuming that its mass remains nearly constant. Answer is 805m/s but i dont know how the equations were used and rearranged to find the final speed.

Please explain each step clearly, especially how you rearranged equations.

Explanation / Answer

s = 2.42*10^9 (given)

u = 275(given)

m = 474 kg(given)

a = F/m = (5.6*10^-2)/474 = 1.183*10^-4 m/s^2

Vf^2 = u^2 +2as (Laws of motion)

Vf^2 = (275)^2 + (2*1.183*10^-4*2.42*10^9) (Just putting the values in the above equation)

Vf = (275*275 + 2*1.183*10^-4*2.42*10^9)^0.5 = 805 m/s

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