Two long straight aluminum wires, each of diameter 0.42 m m , carry the same cur
ID: 3895701 • Letter: T
Question
Two long straight aluminum wires, each of diameter 0.42mm , carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in (Figure 1) . Two long straight aluminum wires, each of diameter 0.42mm , carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in (Figure 1) . Two long straight aluminum wires, each of diameter 0.42mm , carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in (Figure 1) . Two long straight aluminum wires, each of diameter 0.42mm , carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in (Figure 1) . Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =
Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =
Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =
Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =
Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =
|I1| = |I2| =
|I1| = |I2| =
of 1 Two long straight aluminum wires, each of diameter 0.42mm , carry the same current but in opposite directions. They are suspended by 0.50-m-long strings as shown in (Figure 1) . Part A If the suspension strings make an angle of 3.0? with the vertical, what is the current in the wires? Express your answer to two significant figures and include the appropriate units. |I1| = |I2| =
of 1
Explanation / Answer
in equilibrium of wires
tan(3) = Fe / m g
= 2x10^-7 i^2 l / d x m g
where 'i' is current in the wires..
ie., i^2 = m g d x tan(3) / 2x10^-7 l
= pi r^2 l (rho) g d x tan(3) / 2x10^-7 l
=3.14*(0.21)*0.50*9.8*0.052/(2*10^-7)
=1.764*10^-9 Amp
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