Help please. Show work. A projectile proton with a speed of 550 m/s collides ela

Question

Help please. Show work.

A projectile proton with a speed of 550 m/s collides elastically with a target proton initially at rest. The two protons then move along perpendicular paths, with the projectile path at 50 from the original direction. (a) What is the speed of the target proton after the collision? m/ Enter a number (b) What s th e speed of the projectile proton after the collision? X m/s The net external force on the two particle system is zero; thus, the net momentum of the system cannot change. The net momentum along the x axis before the collision must equal that after the collision. Same for the y axis.

Explanation / Answer

m*v1*sin 50=m*v2*sin 40

v1=0.839*v2..(1)

m*500=m*v1*cos 50+m*v2*cos 40

v2=383.04 m/s

v1=321.37 m/s

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