When a gas follows path 123 on the PV diagram in the figure, 418 J of energy flo

Question

When a gas follows path 123 on the PV diagram in the figure, 418 J of energy flows into the system by heat

and -167 J of work is done on the gas (167 J done by the gas).

(a) What is the change in internal energy of the system?

(b) How much energy Q flows into the system if the gas follows path 143? The work done on

the gas along this path is -63.0 J. What net work would be done on or by the system if the system followed

(c) path 12341 and

(d) path 14321?

(e) What is the change in internal energy of the system in the processes described by (c) and (d)?

Explanation / Answer

solution:

a)

delta_U = Q - W

so U3 - U1 = delta_U123 = 418J - (167J) = 251J

b)

delta_U143 = U3 - U1 = 251J

but W143 = 63J

therefore Q =delta_U + W143 = 251J + (63J) = 314J

c)

W1234 = W23 + W41 = 167J - 63J = 104J

d)

- 104J (reverse)

e)

for cycle, delta_U = 0

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