Suppose the two resistors (25 ohms and 35 ohms in a series with a 12-V battery)

Question

Suppose the two resistors (25 ohms and 35 ohms in a series with a 12-V battery) were connected in parallel. What would be a)the current in the circuit?

b)the power expended in the circuit?


A student connects a 10 ohm resistor, a 15 ohm resistor and a 20 ohm resistor in parallel and then connects to a 50-V dc source
a) How much current is in the circuit?

b) How much power is expended in the circuit?


A 30.0 ohm resistor and a 60.0 ohm resistor in parallel are connected to a 120-Vdc source
a) What is (are) the current(s) through the resistors?

b) What is the voltage drop across each resistor?

Explanation / Answer

P=Vi

V=iR

12=iR

Req=25+35=60

a)i=0.2A

b)P=Vi=12x0.2=2.4watts

Req=inverse 1/r1+1/r2+1/r3=4.61ohm

V=ir

50/4.61=i

i=10.8A

P=Vi

P=10.8x50=542.3watts

Req=inverse )1/30+1/60)=20ohm

through resistor 30 ohm

V=iR1

120/30=40A

through 60

V=iR2

i=20A

Voltage drop =120v

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