MASTERING PHYSICS - ELECROMAGNETICS I HAVE ATTATCHED AN IMAGE OF HOW THE SOLUTIO

Question

MASTERING PHYSICS - ELECROMAGNETICS

I HAVE ATTATCHED AN IMAGE OF HOW THE SOLUTION IS SOLVED WITH DIFFERENT INPUT VALUES. I AM TOO BUSY TO SOLVE THIS FOR MYSELF SO I WILL LEAVE YOU TO USE THE IMAGE AS A TEMPLATE TO CORRECTLY SOLVE FOR THIS SAME PROBLEM BUT WITH DIFFERENT VALUES. THANKS. *THE ASSIGNED QUESTION IS BELOW THIS IMAGE.

NOW HERE IS THE SAME QUESTION BUT WITH DIFFERENT INPUT VALUES

3.) Part C

5.) Part E

We calculate capacitive reactive using Eq. 30-25b. Then using the resistance and capacitive reactance we calculate the impedance. Finally, we use Eq.30-27 to calculate the rms current. We calculate the phase angle using Eq. 30-29a. The average power is calculated using Eq. 30-30. The voltmeter will read the rms voltage across each element. we calculate the rms voltage by multi playing the rms current through the element by the resistance or capacitive reactance. Note that science the voltage are out of phase they do not sum to the applied voltage. However, since they 90 Degree out of phase their squares sum to the input voltage. We find the resistance using Ohm's law with the dc voltage and current. When then calculate the

Explanation / Answer

solution: impedennce Z^2 = R^2 + XC^2

capacitie reactance Xc = 1/(2pif c) = 1/(2*3.14 * 50 * 1.2 uF ) = 2653.92 o0hms

so Z^2 = 5200^2 + 2653.92^2

Z = 5838.089 ohms

A. Irms = Vrms/R = 230/5838.089 = 0.0393 A   or 39.2 mA

b. phase angle = tan theta = Xl-XC/R

= -2653.92/5200 = 0.5103
angle = -27.03 deg

C. Powere P = Irms Vrms = 0.0392* 230 * cos (-27.03) = -8.07   Watts

d. V across R = IR = 0.0393* 5200 = 204.36 volts

e. V across C = IXc = 0.0393 * 2653.92   = 104.299 volts

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