First Person to answer both correctly gets full points!! A 24.0 - crn - diameter

Question

First Person to answer both correctly gets full points!!

A 24.0 - crn - diameter coil consists of 50 turns of circular copper wire 2.1 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.60x10 - 3 T/s . The resistivity of copper is 1.68x10 - 8 Ohm . m Part A Determine the current in the loop. Express your answer to two significant figures and include the appropriate units. Part B Determine the rate at which thermal energy is produced. Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

a> emf= no of turns * area * rate of change of field =50* (pi/4) *(0.24)^2 * 8.6*10^-3= 0.019

resistance =[resistivity * number of turns * pi * diameter of coil / (pi*diameter of wire^2/4)] =0.182

current =emf/ resistance =0.104 A

b>heat= current ^2* resistance =1.96*10^-3

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