What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it

Question

What must the charge (sign and magnitude) of a particle of mass 1.45g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660N/C ? Use 9.81m/s2 for the magnitude of the acceleration due to gravity.




What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.6710?27kg for the mass of a proton, 1.6010?19C for the magnitude of the charge on an electron, and 9.81m/s2 for the magnitude of the acceleration due to gravity.
What must the charge (sign and magnitude) of a particle of mass 1.45g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660N/C ? Use 9.81m/s2 for the magnitude of the acceleration due to gravity.




What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.6710?27kg for the mass of a proton, 1.6010?19C for the magnitude of the charge on an electron, and 9.81m/s2 for the magnitude of the acceleration due to gravity.
What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.6710?27kg for the mass of a proton, 1.6010?19C for the magnitude of the charge on an electron, and 9.81m/s2 for the magnitude of the acceleration due to gravity.

Explanation / Answer

1)

F = E*q

F = mg

so, mg = E*q

q = m*g / E

q = 1.45*10^-3 * 9.81 / 660 = 21.552 * 10^-6 C

q = 21.552 uC

2)

F = E*q

F = mg

so, mg = E*q

E = m*g / q

E = 1.67*10^-27 * 9.81 / (1.6*10^-19)

E = 1.0239 * 10^-7 N/C

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