As stack application, the following algorithm ilustrates how postfix is converte

Question

As stack application, the following algorithm ilustrates how postfix is converted into infix 1. Scan expression E from left to right character by character ch = get-next-token(E) 2, while(ch ! # ) do if(ch operand) then push(ch) if(ch = operator) then begin t2 pop() and t1 pop) push(concatenate [t1, ch, t21) end ch = get-next-token(E) end while 3, if ch-,#, while(lemptystack()) pop and display 4. stop Convert the following postfix expression to its infix form as the final product processed by the previous algorithm. WRITE YOUR ANSWER WITHOUT SPACE Answer:

Explanation / Answer

Answer:
A x B ^ C which means (A x B)^C

Explanation : A , B pushed into Stack as they are Operand
Then we get x , which is Operator so A x B

Then C added into Stack, then ^ ...Now the Stack will be A x B ^ C and its the final Answer

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