POSSIBLE HELPER BELOW: - MAY OR MAY NOT NEED (B) Consider the following schema P
ID: 3906461 • Letter: P
Question
POSSIBLE HELPER BELOW: - MAY OR MAY NOT NEED
(B) Consider the following schema PLAYER PlayerID Birth dt Draft year TEAM TcanID City 1204ris Faul 1392Derek Fisher Aug, 197 1580 Josh snith Dec, 198 1597Tyson Charuller Oct, 1582 ay, 1 2009 LA 11ut Rockets 23 Dallas Vavericss 1996 Clippers 2001 PLAYER TEAM PlayerIDTeanID Start date End dateoo1 eaaes 1204 1597 1590 2011 2010 2014 null 2011 null 234 128 1597 2014 nul 1 PlayerlD is a key for Player (P) TeamlD is key for Team (T) (PlayerlD, TeamlD) is a composite key for Player_Team (PT) Show the results of the following Relational Algebra expressions (20 points) ? P.name. T.name (PD Tp PT) (??) TT P.name (P PT Dd ? city."Dallas-or city."Houston. I (ii) p (PP (1-playerid1, 2-draftyear1, 3-> playerid2, 4 -» draftyear2), (TT playerid, draft_year playerid, draft year playerid P - T playerid1 ? draftyear1Explanation / Answer
If you have any doubts, please give me comment...
i)
P.name
T.name
Chris Paul
Clippers
Tyson Chandler
Dallas
Josh Smith
Rockets
ii)
P.name
Tyson Chandler
Josh Smith
iii)
PlayerID
Name
Birth_dt
Draft_year
1204
Chris Paul
May, 1965
2005
iv)
name
Tyson Chandler
v)
P.name
Chris Paul
Tyson Chandler
vi)
t.name
p.name
Mavericks
Tyson Chandler
Vii)
name
Chris Paul
Viii)
name
Chris Paul
Josh Smith
ix)
name
Mavericks
x)
name
Derek Fisher
Note: As per theory, RA queries always gives Unique tuples...
P.name
T.name
Chris Paul
Clippers
Tyson Chandler
Dallas
Josh Smith
Rockets
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