pls hel meee!! TwoDimArr<String> arr= new TwoDimArr<String> (3,5,\"cell\"); arr.

Question

pls hel meee!!

TwoDimArr<String> arr= new TwoDimArr<String> (3,5,"cell");

arr.set(2,1,"tissue");

System.out.println(arr.get(2,1));

System.out.println(arr.get(2,3));

System.out.println(arr.countOccurences("cell"));

TwoDimArr <Double> arr2= new TwoDimArr <Double>(2,3,4.5);

//---------------------------------------------------------------------------------------

output

tissue

cell

14

*The shown constructor takes the dimension information and the initial value of all elements of the array as a parameter.

set:put data to given index

get:return to data from given index

contOccurance:how many times pass the given paremeter in matrix

Explanation / Answer

Given below is the code for the question.
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TwoDimArr.java
==============

public class TwoDimArr<T> {
private T[][] data;
private int rows;
private int cols;
public TwoDimArr(int rows, int cols, T initial){
this.rows = rows;
this.cols = cols;
data = (T[][])new Object[rows][cols];

for(int i = 0; i < rows; i++)
for(int j = 0; j < cols; j++)
data[i][j] = initial;
}

public void set(int r, int c, T value){
if(r >= 0 && r < rows && c >= 0 && c < cols)
data[r][c] = value;
}

public T get(int r, int c){
if(r >= 0 && r < rows && c >= 0 && c < cols)
return data[r][c];
else
return null;
}

public int countOccurences(T value){
int count = 0;
for(int i = 0; i < rows; i++)
for(int j = 0; j < cols; j++)
{
if(data[i][j].equals(value))
count++;
}

return count;
}

}

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