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Need a C Program that prints this! Player-1 it is your turn! Please enter your c

ID: 3925102 • Letter: N

Question

Need a C Program that prints this! Player-1 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: why I'm sorry, I do not understand. Please enter your choice (p)aper, (r)ock, or (s)cissors: 42 I'm sorry, I do not understand. Please enter your choice (p)aper, (r)ock, or (s)cissors: Paper! Player-2 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: r Playerl wins! Paper covers rock! Do you wish to continue? (y/n): y Player-1 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: s Player-2 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: Rock on! Player2 wins! Rock breaks scissors! Do you wish to continue? (y/n): n Program ended with exit code: 0

Explanation / Answer

#include <stdio.h>
#include <conio.h>

main ()
{
char p1, p2, q;
clrscr ();
printf (" Player-1 it is your turn: ");
p1=getche ();
printf (" Player-2 it is your turn: ");
p2=getche ();

if (((p1=='p')||(p1=='P')) && ((p2=='R') || (p2=='r')))

{
  printf (" Player 1 Wins !");
  printf (" Paper Covers Rock");
}

else if (((p2=='p') || (p2=='P')) && ((p1=='r') || (p1=='R')))

{
printf (" Player 2 Wins !");
printf ("Paper Covers Rock");
}

else if (((p1=='r') || (p1=='R')) && ((p2=='s') || (p2=='S')))

{
printf (" Player 1 Wins !");
printf ("Rock Breaks Scissors");
}

else if (((p2=='r') || (p2=='R')) && ((p1=='s') || (p1=='S')))

{
printf (" Player 2 Wins !");
printf ("Rock Breaks Scissors");
}

else if (((p1=='s') || (p1=='S')) && ((p2=='p') || (p2=='P')))

{
printf (" Player 1 Wins !");
printf ("Scissors Cut Paper");
}

else if (((p2=='s') || (p2=='S')) && ((p1=='p') || (p1=='P')))
{
printf ("Player 2 Wins !");
printf ("Scissors Cut Paper");
}

else if (p1==p2)
{
printf (" Nobody Wins !");
printf (" Both Of You Entered The Same Letters");
}

else {

printf (" I am Sorry, I do not uderstand.");
printf (" Enter Only Letters : P,S or R");
}
printf(" Do you wish to continue? (y/n) " );

q=getche ();

if (quit=n){

return 0;

}


getch ();

}

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