Answer this Operations Management subject breifly 7. Pustaka Mutiara Sdn. Bhd pu
ID: 395782 • Letter: A
Question
Answer this Operations Management subject breifly 7. Pustaka Mutiara Sdn. Bhd purchases pens from a supplier in Lembah Klang. The supplier sells the the bookstore at RM2.00 per unit. The cost for the book store to place an order carrying cost is RM0. the stories open for 240 days in a year. The lead time from the time of order placement until receipt is 3 days The company keep 5 days usage of safety stock. pens to is RM23 and the inventory 10 per unit per month. The manager estimates that the daily sales will be 134 units and i Based on the information, determine the Optimal Order Quantity, Number of order and the Time Between Orders i. Based on question above how much safety stock should manager keep on hand then what is the 8. Explain THREE (3) limitations of job expansion. 9. MFO Construction Sdn. Bhd plans to construct a new project in the development of new township. objective of safety stock? The Information related to the project is follow Activity Immediate Predecessor (s) Time (weeks) E,F G.H I. Draw the precedent diagram Il. Calculate Earliest Finish and Latest Start for activity E till Ibased on the precedent diagram above. IlI. By using the information in question 1 (b), identify the critical path V. By using the information in question 1 (b), determine the project completion time. V. If activity C were delayed by 8 days, what would be the impact on the project completion? Explain your answer 10. Briefly discuss THREE (3) types of inventory 11. Consider the following product structure. If 50 units of Product A are allocated, how many units of B, c,D, and E are needed? B(2) 12. Briefly explain THREE (3) dimension of quality for goods 13. Describe THREE (3) productivity variablesExplanation / Answer
Answer to question I :
The precedence diagram as follows :
A
B
C
D
E
F
H
G
I
Answer to question III:
The possible paths and their corresponding durations as follows:
A-B-D-H-I = 9 + 7 + 6 + 5 + 3 = 30weeks
A-B-E-G-I = 9 + 7 + 9 + 5 + 3 = 33 weeks
A-C-F-G-I = 9 + 3 + 4 + 6 + 3 = 25 weeks
Since A-B-E-G-I has the longest duration, it is the critical path
CRITICAL PATH : A-B-E-G-I
Answer to question IV :
Project completion time is same as ration of critical path.
Therefore , project completion time is 33 weeks
Answer to question II :
Since activity E lies on the critical path, it will have ZERO slack
Therefore its :
Earliest start time = Latest start time
Earliest finish time = Latest finish time
Latest start of activity E
= Sum of durations of A and B
= 9 + 7 weeks
= 16 weeks
Earliest finish of activity E
= Sum of durations of A , B and E
= 9 + 7 + 9 weeks
= 25 weeks
EARLIEST FINISH OF ACTIVITY E = 25 WEEKS
LATEST START OF ACTIVITY E = 16 WEEKS
Answer to question V :
Slack of activity C
= Duration A-B-E-G-I – Duration A-C-F-G-I
= 33 – 25
= 8 WEEKS
Thus , activity C can be delayed by maximum 8 days without hampering the project completion time
THERE WILL BE NO IMPACT ON PROJECT COMPLETION TIME
A
B
C
D
E
F
H
G
I
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