Problem 10-1 Specifications for a part for a DVD player state that the part shou
ID: 404463 • Letter: P
Question
Problem 10-1 Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A.a. What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.)
Percentage of parts %
b. Within what values will 99.74 percent of sample means of this process fall, if samples of n = 8 are taken and the process is in control (random)? (Round your answers to 2 decimal places.)
Lower value , Upper value
Please explain step-by-step for solution. Problem 10-1 Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A.
a. What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.)
Percentage of parts %
b. Within what values will 99.74 percent of sample means of this process fall, if samples of n = 8 are taken and the process is in control (random)? (Round your answers to 2 decimal places.)
Lower value , Upper value
Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A. What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.) Within what values will 99.74 percent of sample means of this process fall, if samples of n = 8 are taken and the process is in control (random)? (Round your answers to 2 decimal places.) Please explain step-by-step for solution. Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A. Specifications for a part for a DVD player state that the part should weigh between 24.5 and 25.5 ounces. The process that produces the parts has a mean of 25.0 ounces and a standard deviation of .25 ounce. The distribution of output is normal. Use Table-A. What percentage of parts will not meet the weight specs? (Round your "z" value and final answer to 2 decimal places. Omit the "%" sign in your response.) Within what values will 99.74 percent of sample means of this process fall, if samples of n = 8 are taken and the process is in control (random)? (Round your answers to 2 decimal places.)
Explanation / Answer
you need to find your critical values (z) first:
z=(sample - population mean)/standard deviation
Which here means
z1= (24 - 24.5)/.2 = -2.5
z2= (25- 24.5)/.2 = 2.5
this means you dvd players will fall within plus or minus 2.5 standard deviations away from the mean.
Now using either a z-table in you book or you handy dandy ti-calculator you find the probability.
For the calculator:
P(meeting specs) = normalcdf(-2.5,2.5) <----- [2nd] [distr] [normalcdf]
you want P(of not meeting specs) so do 1-Ans
P(not meeting specs) = .0124
For Part B:
95.44% should be a number you have devoted to memory. It means within 2 standard deviation of the mean.
using the equation from before:
2=(x-24.5)/.2
x=24.9
-2=(x-24.5)/.2
x=24.1
therefore your values wall fall in the range of [24.1,24.9]
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