QUESTION 3 Through extensive research on Facebook, we were able to determine tha

Question

QUESTION 3 Through extensive research on Facebook, we were able to determine that the students in our Bi 213 class, and their families, have a total of 128 cats, of which 88 have the recessive short hair phenotype. Assume that these 128 cats form a single population that is in Hardy-Weinberg equilibrium. How many carriers (cats with a single copy of the recessive short hair length allele) are there in this population? (4 pts) QUESTION 4 Do you think that Hardy-Weinberg Equilibrium is a good model to apply to this population? (1 pt) Yes No

Explanation / Answer

3 B.

Since 88 show recessive genotype, we calculate the frequency as 88/128 and multiply by 100 to get 69%.

This gives q2 as 0.69. Hence q would be 0.83.

So, p would be 1 - 0.83 = 0.17.

2pq would be 2 x 0.83 x 0.17 = 0. 28.

The number of cats which are carriers are 0.28 x 128 = 36.

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4. b NO.

In the Hardy Weinberg equation, the dominant allele should have a higher frequency than the recessive genotype. Since this is not seen in the above case, the Hardy Weinberg equilibrium does not seem to be a good model.

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