At Isogen Pharmaceuticals, the filling process for its asthma inhaler is set to
ID: 410189 • Letter: A
Question
At Isogen Pharmaceuticals, the filling process for its asthma inhaler is set to dispense 150 milliliters (ml) of steroid solution per container. The average range for a sample of 6 containers is 6 ml. Use the accompanying table to establish control limits for sample means and ranges for the filling process.
The UCL Upper RUCLR equals ____ ml and the LCL Subscript Upper RLCLR equals ____ ml. (rounded to two decimal places.)
The UCL UCLx equals _____ ml and the LCLLCLx equals ____ ml. (rounded to two decimal places.)
Explanation / Answer
To be Calculated:
a) Upper Control Limit of Range Chart, UCL-R
b) Lower Control Limit of Range Chart, LCL-R
c) Upper Control Limit of X-bar Chart, UCL-X
d) Lower Control Limit of X-bar Chart, LCL-X
Given Values:
a) Average of X, X-bar = 150 ml.
b) Average of Ranges, R-bar = 6 ml.
c) Number of Samples, N = 6 containers
Solution:
a) Upper Control Limit of Range Chart, UCL-R can be calculated as;
UCL-R = (D4 x R-bar)
Using, the accompanying table, control limits can be established as;
D4 (for N = 6) = 2.004
UCL-R = 2.004 x 6 = 12.024
UCL-R = 12.02 ml.
b) Lower Control Limit of Range Chart, LCL-R can be calculated as;
LCL-R = (D3 x R-bar)
Using, the accompanying table, control limits can be established as;
D3 (for N = 6) = 0
LCL-R = 0 x 6 = 0
LCL-R = 0 ml.
c) Upper Control Limit of X-bar Chart, UCL-X can be calculated as;
UCL-X = X-bar + (A2 x R-bar)
Using, the accompanying table, control limits can be established as;
A2 (for N = 6) = 0.483
UCL-X = 150 + (0.483 x 6) = 150 + 2.898 = 152.898
UCL-X = 152.90 ml.
d) Lower Control Limit of X-bar Chart, LCL-X can be calculated as;
LCL-X = X-bar - (A2 x R-bar)
Using, the accompanying table, control limits can be established as;
A2 (for N = 6) = 0.483
LCL-X = 150 - (0.483 x 6) = 150 - 2.898 = 147.102
LCL-X = 147.10
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