This Question: 4 pts 250136 (0 complete) This Test: 100 pts poss Question Help T
ID: 418536 • Letter: T
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This Question: 4 pts 250136 (0 complete) This Test: 100 pts poss Question Help Three activities are cardidates for crashing on a project network for a large computer installation (all are, of course, critical). Activity details are in the following table: Total Cost Normal Time Crash Time Normalwith Activity (days) (days) 6 ?mmediato Predecessor(s) Cost $8,000 $6,400 $1,400 $3,100 $4,200 $6,400 Crashing a) Activity that should be crashed first to reduce the project duration by 1 day is b) Activity that should be crashed next to reduce the project duration by one additional day is ) Total cost of crashing the project by 2 days (Enter your response as an integer) Enter your answer in the answer boxExplanation / Answer
Early start of A = 0
Early finish of A = 0 + 7 ( 7 days)
Early start of B = 7
Early finish of B = 7 + 4 ( 11)
Early start of C = 11
Early finish of C = 11 + 11 ( 22)
Latest finish of C = 22
Latest start of C = 22 - 11 (11)
Latest finish of of B = 11
Latest start of B = 11 - 4 ( 7)
Latest finish of A = 7
Latest start of A = 7 - 7( 0)
a) Activity that should be crashed first is A
b) Activity that should be crashed next is B
c) Cost of crashing the activity by 2 days = $ 6400 + $1550
Cost of crashing the activity by 2 days = $ 7,950
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