Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

b) To reduce the duration of the project to 10 weeks at the least? cost, the fol

ID: 431368 • Letter: B

Question

b) To reduce the duration of the project to 10 weeks at the least? cost, the following is the order of what needs to be followed while crashing the? activities:
The first activity to crash is ___ by 2 weeks at a per week crashing cost of ____ dollars.
?Next, one should crash activity (answer from above) and activity ____ by 2 weeks weeks for an additional total per week crashing cost of ____ dollars.
?c) New requirements are to reduce the project to 7 weeks. Continuing to crash the activities from 10 weeks based on the above crashing already? completed, the following is the order for? crashing:
Next activity to crash in order is ___ by 2 weeks weeks at a per week crashing cost of ____ dollars.
?Next, one should crash activity ___and activity E by 1 week at a total per week crashing cost of ___ dollars.
Total cost of crashing the project to 7 weeks? = ___ dollars.


Thank you in advance!
Problem 3.32 Kimpel Products makes pizza ovens for commercial use James Kimpel, CEO, is contemplating producing smaller ovens for use in high school and college kitchens The activities necessary to build an experimental model and related data are listed in the following table Normal Time Crash Time Normal with Activity (weeks) (weeks) Cost Crashing Immediate Predecessorte 2$1,000 $1,650 $2,000 $2,800 $300 $300 $1,500 $1,780 $950 $1,250 $4,000 $5,200 $1,500 $2000 D, E

Explanation / Answer

Path and Duration are:

ADG = 3+7+4 = 14

BEG = 2+6+4 = 12

CF = 1+2 = 3

Crashing cost for activity:

b) From path ADG, crash D by two days as cost is minimum

The first activity to crash is D by 2 weeks with weekly crashing cost = 280$

Now ADG and BEG have same duration of 12 week.

Next, one should crash G by 2 weeks for additional weekly crashing cost of 500$

c) G cannot be crashed further

Crash D & E by 2 weeks each. Crashing cost of D is 280$ and E is 300$ per week

Finally, crash A by 1 week with cost of 650$ and E by 1 week at cost of 300$ per week

Total cost of crashing to 7 weeks = 280*2 + 500*2 + 280*2 + 300*3 + 650 = 3370$

Normal cost Crash cost Excess cost A 1000 1650 650 B 2000 2800 800 C 300 300 0 D 1500 1780 280 E 950 1250 300 F 4000 5200 1200 G 1500 2000 500