to identify only one. I1 Consider the frequency of trips between departments mat

Question

to identify only one. I1 Consider the frequency of trips between departments matrix shown in Figure 3.12. For each distance metric you have ulearned, determine the flow times distance for cach pair of departments. Add these quantities and determine which metric yields the least sum of flow times distance. Alter the configuration so that the departments are closer to one another and the new block plan is feasible. While altering the positions of departments, try to reduce the overall flow times distance al least 15% over the previous configuration. Note that you must use the same shapes, lengths, and breadths you assumed before. Also note that you may have to generate a different block plan for each distance metric. Oepartment 1 Cepartreent 2 Department 3 Deparimont 4 Departmant S Department 6 Departmene 1 Department 2 Depate13 19 Department o 30 FIGURE 3.12 Frequescy of Irigs thetwecn deparlmerts matris

Explanation / Answer

The question is about layout of six departments based on the frequencies of trips between the departments so that the total travelled distance between the departments is minimum.

The given freqiencies of trips between Departments (represented by Di) along with totals are given in the following table

Highest frequency (38) is between Departments numbered as D5 and D6, therefore these should be adjacent, next highest is 33 between D1 and D2 so should be close by, next highest figure is 19 between D4 and D5.

Let us begin with the following layout

The above mentioned distance matrix is corresponding to the above mentioned layout and the resultant frequency distance matrix is as follows:

In case we interchange the position of D3 and D4, the new layout is as follows:

The revised distance matrix and Net F * d matrix are as follows:

416

Hence the second layout is better than the first one.

D1 D2 D3 D4 D5 D6 TOTAL D1 33 7 3 1 4 48 D2 33 5 2 9 49 D3 7 5 8 10 8 38 D4 3 8 19 11 41 D5 1 2 10 19 38 70 D6 4 9 8 11 38 70 TOTAL 48 49 38 41 70 70

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