Hi having a problem with this Hardy Weinberg stuff Problem 1 In population of 65

Question

Hi having a problem with this Hardy Weinberg stuff Problem 1 In population of 6540 moths 800 moths are darkgray dark gray is dominant to light gray. what are the frequenciesfor the genotypes in the population(recall that there are 3genotypes present). show all calculations Problem 2 In the next generation dominant moths were able toevade predators more efficiently than resessive peppered moths. therecessive moths were now targets. with in the population 50000 geteaten by predatory birds and removed from the population . how willthe next generation s genetpic frequencies be altered. show allcalculations thanks for your help Hi having a problem with this Hardy Weinberg stuff Problem 1 In population of 6540 moths 800 moths are darkgray dark gray is dominant to light gray. what are the frequenciesfor the genotypes in the population(recall that there are 3genotypes present). show all calculations Problem 2 In the next generation dominant moths were able toevade predators more efficiently than resessive peppered moths. therecessive moths were now targets. with in the population 50000 geteaten by predatory birds and removed from the population . how willthe next generation s genetpic frequencies be altered. show allcalculations thanks for your help

Explanation / Answer

1) okay, 6540 - 800 = 5740 homozygous recessive moths. Knowingthat, we can divide 5740 by 6540 to find the frequency of thathomozygous recessive genotype(0.877675841). That's b. Knowingthat, B + b = 1, so 1 - 0.877675841 = B = 0.122324159. Now B x b =107360959 = heterozygousfrequency. B^2 = homozygousdominant freq = 0149631999 2) By 50000, do you mean 5000? 50,000 would be a negative amount ofmoths. :) I'm going to assume 5000. 6540 - 5000 - 800 = 740recessive moths. Now the same as above. 740/6540 = 0.113149847 = b.1 - b = 0.886850153 = B. B * b = 0.10034695 = heterozygousfrequency. B^2 = 0.786503194 = homozygous dominant frequency Hope that helps!

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