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help with steps please An engineer is considering the size of a reservoir for fl

ID: 453242 • Letter: H

Question

help with steps please An engineer is considering the size of a reservoir for flood control in the northern part of Germany. The size of the of the reservoir is closely related to the annual rainfall. In addition there will be reparation costs from damages when the amount of rainfall exceeds the design capacity. If such damage occurs, it is estimated that the annual reparation cost will be 2.3% of the capital investment. The probabilities of specific amounts of rainfall per year and the estimated investment costs of the reservoir are given below. Using an interest rate of 8% per year and a study period of 11 years, determine the appropriate investment on the basis of AW.

Explanation / Answer

Annual Rainfall

Probability of higher rainfall

Estimated investment

110

0.6

2500000

120

0.2

2550000

130

0.1

2600000

140

0.055

2650000

150

0.045

2700000

Firstly, we need to find out expected investment value using the probabilities.

Expected investment is 0.6*2500000+0.2*2550000+0.1*2600000+0.055*2650000+0.045*2700000

= 2537250

Now, whenever there is an exceeding rainfall, we incur an expense of 2.3% of investment value.

I.e. 2.3% of 2537250 = 58356.75.

This expense happens annually over a period of 11 years. We have to find the present value of each of these future expenses. Rate of interest = 8%

For example, PV of 58356.75 from one year = 58356.75/(1+0.08)^1 = 54034.03

Similarly, from 2 years = 58356.75/(1+0.08)^2 = 50031.51

We calculate PV for all 11 years and add up the amount to find out the PV of the future cash out flows.

Year

Expense

PV of expense

1

58356.75

54034.03

2

58356.75

50031.51

3

58356.75

46325.47

4

58356.75

42893.95

5

58356.75

39716.62

6

58356.75

36774.65

7

58356.75

34050.60

8

58356.75

31528.34

9

58356.75

29192.90

10

58356.75

27030.47

11

58356.75

25028.21

Total expense

416606.75

So, the total investment that can be put up on this project = expected investment based on probabilities + PVs of future cash expenses = 2537250 + 416606.75 = $2953856.75

Annual Rainfall

Probability of higher rainfall

Estimated investment

110

0.6

2500000

120

0.2

2550000

130

0.1

2600000

140

0.055

2650000

150

0.045

2700000