Which of the following CH_4 samples contains the greatest number of moles of CH_

Question

Which of the following CH_4 samples contains the greatest number of moles of CH_4? 0.356 moles CH_4 4 65 times 10^23 CH_4 molecules 6.78 times 10^1g CH_4 8.90g CH_4 None of the above Liquid oxygen boils at -182.9 degree C. Express the boiling point of liquid oxygen in degree F. -384.4 -352.4 -320.4 -297.2 -76.8 The oxidation number of iron in Fe_2O_3 is -2 +1 +2 -3 +3 The ground stare condensed electron configuration of Ga is [Ar]4s^23d^104d^1 [Ar]4s^23d^11 [Kr]4s^23d^104p^1 [Ar]4s^23d^104p^1 [Ar]4s^24d^104p^1 What volume (mL) of a concentrated solution of magnesium chloride (9.00M) must be diluted to 350mL to make a 2.75M solution of magnesium chloride? 107 350 50.0 2.75 45.0 The elements in groups 1A, 7A, and 8A are called respectively alkaline earth metals, halogens, and chalcogens halogens, transition metals, and alkali metals alkali metals, halogens, and noble gases alkaline earth metals, transition metals, and halogens alkali metals, halogens, and noble gases

Explanation / Answer

14) one mole = 6.023 X 10^23 molecules

so 1 molecule = 1/ 6.023 X 10^23 moles

molecular weight of CH4 = 16

so 16grams of CH4 = 1mole

1 gram = 1/16 moles

b) moles in 4.65 X 10^23 molecules = 4.65 X 10^23 / 6.023 X 10^23 = 0.772 moles

c) moles in 6.78 grams = 6.78 / 16 = 0.423 moles

d) moles in 8.90 grams = 8.90/ 16 = 0.556

so answer is 4.65 X 10^23 molecules

15 ) Let us know the relation between 0C and 0F

0C = (9/50C + 32) 0F

so answer is -297.220F

16) let oxidation number of Fe =x

2x + 3(-2) = 0

2x = 6

x =+3

17) the electronic configuration is Ar 3d10 4s2 4p1

18) we will use M1V1 = M2V2

M1 = 9M

V1 = ?

M2 = 2.75

V2 = 350 mL

V1 = 2.75 X 350 / 9 = 106.94mL

19) 1A : alkali metals

7A : halogens

8A : noble gases

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