x Infrared spectroscop x X MolPorts c11H140 x G ca-11N-Google se x C chegg Study

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x Infrared spectroscop x X MolPorts c11H140 x G ca-11N-Google se x C chegg Study IGuide x D homework answers x G vinyli Google sea x NMR Ta b x vi Wiley PLUS 4 C Secure hittps://edugen.vvileyplus.com/edugen/student/mainfr.uni 'Wiley PLUS: MrWilsrdPLLIS Wiley PLUS Klein, Organic Chemistry, 2e ORGANIC CHEMISTRY (CHEM 3361 3362) BACK NEXT ASSIGNMENT RESOURCES Question 5 uestion 6 Question Question 10 Queslian 11 Question 12 Question 13 Question 15 Question Question 17 Question 18 1 4 Review Score Obiective 426 PM Ask me anything

Explanation / Answer

Presence of a triplet at 1 ppm for 6H, a multiplet at 1.5 ppm for 4H and a triplet at 2.5 ppm for 4H in proton NMR indicates two symmetrical CH3CH2CH2 groups. This is also supported by the presence of three signals in 13C NMR. Since there is no other carbon in the molecule, so a singlet for 1H at 2 ppm indicates a NH group. Thus, joining of these two fragments will give dipropyl amine (CH3CH2CH2NHCH2CH3CH3). M+ of MS ie 101 along with the fragmentation pattern correlates with this structure. IR also supports this structure.

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