B. Solve the differential equation using the boundary conditions: C = C 1 at r =
ID: 476745 • Letter: B
Question
B. Solve the differential equation using the boundary conditions:
C = C1 at r = R1 and C = 0 at r = R2.
Explanation / Answer
the mass balance equation becomes for a differential element
NAr*4PIr2|r- NAr*4PIr2|r+dr =0 (1)( under steady state, rate of mass in = rate of mass out)
NAr= Flux = -DAB* dCA/dr
Eq.1 can be written in differential form
d/dr(NAr*r2) =0
when integrated, NAr*r2= C', Where C' is integration constant
Nr = C'/r2,
-D*dC/dr = C'/r2, D is the diffusivity , dC/dr is concentration gradfient
-D dC= C'dr/r2
D*dC= -C'dr/r2
D*C = C'/r +C'', where C'' is another integration constant
at r= R1, C= C1 boundary condition (1) and r= R2, C2=0 boundary condition (2)
D*C1= C'/R1 + C'' (1) and D* 0 = C'/R2 +C" (2)
from Eq.2, C'/R2= -C''
from Eq.1
D*C1= C'/R1-C"/R2
C"(1/R1-1/R2)= D'C1
C'' = DC1 (1R1-1/R2)
C'= -DC1R2/(1R1-1/R2)
D*C = -DC1R2/ (1/R1-1/R2)*r+DC1/(1/R1-1/R2)
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