Complete the table below. Round each of your entries to 2 significant digits. Yo

Question

Complete the table below. Round each of your entries to 2 significant digits. You may assume the temperature is 25 C. conjugate acid congugate base x In 2 Consider the following mechanism for the reaction between nitric oxide and oxygen: NO (g) 0,(9) NO (g) to (g) NO (g) o(g) NO 2(g) Write the chemical of the overall reaction: Are there any this mecha If there are intermediates, write Enter the chemical formula of a binary molecular compound of hydrogen and a Group 4A element that can reasonably be expected to be less acidic in down their chemical aqueous solution than GcH a, e.g. have a smaller Ka. Put a between each chemical formula, if there's more than The rate of a certain reaction is given by the following rate law: rate NOT O, Use this information to answer the questions below. Vhat is the reaction order in NO? What is the reaction order in O2 What is overall reaction order? A certain reaction is first order in N, and second order in H 2. Use this information to complete the table below. Round each of your answers to 3 significant digits. AL certain concentration ofNO and 02, rate of is 4.0 10SM/s, what would the initial rate of the reaction ber the concentration NO were doubled? Round [N2] CH2] initial rate of reaction your answer to 2 significant digits. The rate of the to be 0.880 M/s when 1.6M and CO 0.15 M. Calculate the of the rate constant. Round your answer to 2 significa digit

Explanation / Answer

.If a proton (H+) is removed from an acid, it becomes a conjugate base.

Hence H2S is conjugate acid for HS- . since Ka*Kb= 10-14, Ka = 10-14/ (1.8*10-7) = 5.555*10-8

Conjugate base for HF is F-, Kb= 10-14/ (6.8*10-4) =1.47*10-11

Conjugate base for HNO2 is NO2-, Kb= 10-14/ 4.5*10-4 =2.22*10-11

2.Group IV-A elements comprise of Titanium , Zr, Halfnium hafnium (Hf) and rutherfordium (Rf). TiH2 is less acidic than GeH4.

3.Let the rate –rA= K[N2]1[H2]2 , k is rate constant

given [N2] =1.25 and [H2] =1.74M and rate = 0.812M/S

K= -rA/ [ [N2] [H2]2 = 0.812/ {1.25*(1.74)2} =0.2145/M2.sec

When [N2] =.425 and [H2] =1.74M, -rA= 0.2145*0.425 *(1.74)2 =0.27604 M/s

For [N2] =0.517M and [H2] =4.21M, -rA= 0.2145*0.517*(4.21)2 = 1.97 M/s

4.

4. overall reaction is obtained by addition of Eq.1 and Eq.2

Gence NO+O2+NO --à2NO2 or 2NO+O2--à 2NO2

The intermedicate isd O(g)

5.

5. The order is the power to which the concentration term in the rate expression is raised.

Rate = K[NO]2 [O2] , the reaction is 2nd order with respect to [NO] and 1 with respect to [O2]

Overall order is sum of the orders = 2+1=3

Given –rA = K[NO]2 [O2] =4*105 M/S

When [NO] is doubled, the rate becomes –rA= K[ 2NO2]2 [O2] =4[NO]2 [O2] =4*4*105 M/s =16*105 M/s

for [NO] = 1.6M and [O2] =0.45M, 0.880= K (1.6)2 *(0.45), K = 0.7638/M2.sec

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