A patient is suspected of having low stomach acid, a condition known as hypochlo

Question

A patient is suspected of having low stomach acid, a condition known as hypochloridia. To determine whether the patient has this condition, her doctors take a 15.00 mL sample of her gastric juices and titrate the sample with 0.000369 M KOH. The gastric juice sample required 8.30 mL of the KOH titrant to neutralize it. Calculate the pH of the gastric juice sample. Assume the sample contained no ingested food or drink which might otherwise interfere with the titration. For the patient to be suffering from hypochloridia, the pH of the gastric juices from the stomach must be greater than pH 4. Does the patient have hypochloridia?

Explanation / Answer

Moles of KOH=molarity of KOH*Volume of KOH=0.000369 mol /L*0.0083 L=3.0627*10^-6 mol

one mole of KOH is neutralizes one of acid.

Molarity of juice=3.0627*10^-6 mol/(15*10^-3)=0.000204 M

pH=-log [0.000204 M]=3.68

AS the pH is less than 4, the patient doesnot suffer from hypochlorida

No

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