You are treating a skin infection by a bacteria in a human. You notice that ther

Question

You are treating a skin infection by a bacteria in a human. You notice that there are two genotypes of bacteria in the infection, C1 and C2. You first check to see what the relative fitness of the two types before treating the patient. You give an antibiotic and recheck the fitnesses with the results shown i the table.

For each of these two situations, calculate what the frequency of allele 1 would be for the next TWO generations, starting from p=.2.

Which of these alleles is resistant to the antibiotic?

If you could leave the infection untreated by antibiotics, what would the frequency of the resistant type be after a long time?

**Please show your work!!

Thanks!

Explanation / Answer

Ans.) As given in that the relative fitness of C1 is 1, it means its obeying Hardy Weinberg equation as the allelic frequency is constant. Therefore the frequency would remain same as p= 0.2 after generations. The relative fitness of C2 in absence of antibiotic is more than more 1 which indicates that the C2 genotype is expressed in abundance. But in presence of antibiotic the expression of C2 genotype reduced.

C1 is resistant to the antibiotic as its fitness is same for C1. It do not display any change towards application of antibiotics.

If the infection is left untreated, bacteria develop resistant by horizontal gene transfer and nullify the effect of antibiotic. Consequently the cells will perform reproduces by conjugation or any other reproduction process and transfers the resistant allele. It result in development od bacterial resistance towards the antibiotics.

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