Given the following equilibrium constants at 417 degree C, Na_2O(s) 2Na(l) + 1/2

Question

Given the following equilibrium constants at 417 degree C, Na_2O(s) 2Na(l) + 1/2 O_2(g) K_1 = 2 times 10^-25 NaO(g) at Na(l) + 1/2 O_2(g) K_2 = 7 times 10^-5 Na_2O_2(s) 2 Na(l) + O_2(g) K_3 = 2 times 10^-29 NaO_2(s) Na(l) + O_2(g) K_4 = 1 times 10^-14 determine the values for the equilibrium constants for the following reactions: a. Na_2o(s) + 1/2 O_2 (g) Na_2O_2 (s) Equilibrium constant = b. Nao(g) + Na_2O(s) Na_2O_2(s) + Na(l) Equilibrium constant = c. 2NaO(g) Na_2O_2(s) Equilibrium constant =

Explanation / Answer

In these type of questions compare reactions to that given in question.

I will name reactions with constants K1,K2,K3 & K4 as A,B,C & D

so,
for a)   A - C   is the reaction. Hence, Equilibrium constant = K1/K3 = 10^4

b)   B + A - C   is the reaction. Hence, Equilibrium constant = K2 * K1/K3 = 7* 10^(-1)

c)   2B - C ->   B + B -C is the reaction. Hence, Equilibrium constant = K1 * K1/K3 = 2* 10^(-21)

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