Make the aqueous solutions, which contain 1 mole of solute per 100 mol of solven

Question

Make the aqueous solutions, which contain 1 mole of solute per 100 mol of solvent. You will need 300 mL of each acid solution and 600 mL of the NaOH. Assume that 1 liter of water contains 55.5 moles, and add the necessary amount of solute to produce the 1 to 100 molar ratio. Please perform the necessary calculations for these solutions before arriving at lab. HCI Concentrated HCI (molarity 12.1) is 36% by volume, with a molar mass of 36.46g/mol. NaOH NaOH has a molar mass of 40.00 g/mol. CH_3COOH Concentrated acetic acid has a density of 1.049g/mL, with a molar mass of 60.05 g/mol. For the purposes of these calculations, you may assume that it is pure acetic acid. H_2O Water has a molarity of 55.5 and a density of 1.000 g/mL.

Explanation / Answer

number of moles of HCl = molarity * volume (L)

= 12.1 mol/L*0.3 L

= '3.63 mol

mass of HCl = 3.63 mol * 36.46 gm/mol

= 132.35 gm

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