please answer the following questions. with an explanation please. Mass of cruci
ID: 480715 • Letter: P
Question
please answer the following questions. with an explanation please.Mass of crucible and cover : 22.76
mass of crucible , cover and solid hydrate : 23.75
mass od crucible , cover and residue: 23.55
Please find:
1. mass of solid hydrate
2. mass of residue
3 mass of water lost
4 percentige of water in the unknown hydrate
5.molar mass of anhydrous
6. number of moles of water per mole of unkown
7. moles of water in hydrate
8. mole of salt in a hydrate
9. formula of a hydrate
unknown: CaSO4
without publisher's prior permission. Violators Print prosecuted. private use only. No part of book may be reproduce ing is for personal, will be D. Percent water in a Hydrate 22.16 of cruable and cover 23.75 Mass of crucible, cover, and solid hydraae 23- Mala of crucible, cover, and residue Calculations and Results Mas of solid hydrate Mass of residue Mass of Ho lost Peroenuage of Hoin the unknown hydrate hn okur Foin ula miss of anhydrous salt if furnished) Number of moles of water per mole of unknown hydrate Casa Moles of mater in Hydrate Mole. of salt in a Hydr dhe Formula g a Hydrate
Explanation / Answer
Answer:
1) mass of solid hydrate = (mass of crucible , cover and solid hydrate) - (Mass of crucible and cover)
= 23.75 - 22.76
= 0.99
2) Mass of residue = (mass of crucible , cover and residue) - (Mass of crucible and cover)
= 23.55 - 22.76
= 0.79
3) Mass of water lost = (mass of solid hydrate) - (mass of residue)
= 0.99 - 0.79
= 0.2
4) Percentage of water:
Mass of solid hydrate = 0.99
mass of water = 0.2
0.99 assume as 100%
0.99 ............ 100
0.2 ............ ?
= (0.2 x 100)/0.99
= 20/0.99
= 20.25%
5) molar mass of anhydrous CaSO4:
Ca atomic weight = 40
S atomic weight = 32
Oxygen atomic weight = 16
Molar mass = 40 + 32 + (16 x 4)
= 40 + 32 + 64
= 136
6) Number of moles of water per mole of unknown
residue = 0.74
water = 0.2
0.74 .............. 0.2
136 ............... ?
= 36.75
Its the value of two moles of water.
7) moles of water in hydrate:
water weight = 0.2
water molecular weight = 18
moles = weight / molecular weight
= 0.2 / 18
= 0.0111
8) moles of salt in Hydrate:
salt weight or residue = 0.74
molecular weight = 136
moles = 0.74/136
= 0.0054
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