Calculate and report the mass (grams) of iron in the 250 mL flask which your unk

Question

Calculate and report the mass (grams) of iron in the 250 mL flask which your unknown was taken. (Don't forget to take account of the second dilution of your unknown).
I calculated the iron concentration of the unknown to be 2.338 x 10^-3.
Here's how the solution was diluted -
Your unknown solution was put into a 250 volumetric and filled to the mark. We analyzed this solution after diluting it 4x: you took 25 mL from the 250 mL flask and diluted to 100. Calculate and report the mass (grams) of iron in the 250 mL flask which your unknown was taken. (Don't forget to take account of the second dilution of your unknown).
I calculated the iron concentration of the unknown to be 2.338 x 10^-3.
Here's how the solution was diluted -
Your unknown solution was put into a 250 volumetric and filled to the mark. We analyzed this solution after diluting it 4x: you took 25 mL from the 250 mL flask and diluted to 100.
I calculated the iron concentration of the unknown to be 2.338 x 10^-3.
Here's how the solution was diluted -
Your unknown solution was put into a 250 volumetric and filled to the mark. We analyzed this solution after diluting it 4x: you took 25 mL from the 250 mL flask and diluted to 100. Your unknown solution was put into a 250 volumetric and filled to the mark. We analyzed this solution after diluting it 4x: you took 25 mL from the 250 mL flask and diluted to 100.

Explanation / Answer

Let the mass of iron be "m"

Molecular weight = 55.845 gms

COncentration = moles / volume in L

Moles = mass / Molecular weight

Initial Concentration = 0.0716m

After dilution to 100ml ; M is new concentration

25*0.0716m = 100*M

M/m = 0.0179

we have given

M = 2.338*10^-3

2.338*10^-3 = 0.0179m

m = 0.1306 gms of Iron

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