Calculate [OH - ] and pH for each of the following solutions. (a) 0.0042 M NaOH

Question

Calculate [OH -] and pH for each of the following solutions. (a) 0.0042 M NaOH (b) 0.0761 g of CsOH in 450.0 mL of solution (c) 56.2 mL of 0.00390 M Sr(OH)2 diluted to 600 mL (d) A solution formed by mixing 13.0 mL of 0.000130 M Sr(OH)2 with 55.0 mL of 7.4 x 10-3M NaOH Calculate [OH -] and pH for each of the following solutions. Calculate [OH -] and pH for each of the following solutions. Calculate [OH -] and pH for each of the following solutions. Calculate [OH -] and pH for each of the following solutions. (a) 0.0042 M NaOH (a) 0.0042 M NaOH (a) 0.0042 M NaOH (a) 0.0042 M NaOH (b) 0.0761 g of CsOH in 450.0 mL of solution (b) 0.0761 g of CsOH in 450.0 mL of solution (b) 0.0761 g of CsOH in 450.0 mL of solution (b) 0.0761 g of CsOH in 450.0 mL of solution (c) 56.2 mL of 0.00390 M Sr(OH)2 diluted to 600 mL (c) 56.2 mL of 0.00390 M Sr(OH)2 diluted to 600 mL (c) 56.2 mL of 0.00390 M Sr(OH)2 diluted to 600 mL (c) 56.2 mL of 0.00390 M Sr(OH)2 diluted to 600 mL (d) A solution formed by mixing 13.0 mL of 0.000130 M Sr(OH)2 with 55.0 mL of 7.4 x 10-3M NaOH (d) A solution formed by mixing 13.0 mL of 0.000130 M Sr(OH)2 with 55.0 mL of 7.4 x 10-3M NaOH (d) A solution formed by mixing 13.0 mL of 0.000130 M Sr(OH)2 with 55.0 mL of 7.4 x 10-3M NaOH (d) A solution formed by mixing 13.0 mL of 0.000130 M Sr(OH)2 with 55.0 mL of 7.4 x 10-3M NaOH

Explanation / Answer

a) OH = 0.0042

pOH = -log0.0042 = 2.37

pH = 11.62

2) [OH] = (0.0761/150)/0.45 = 0.001127

pOH = -log 0.001127 = 2.95

pH = 11.05

3) moles of Sr(OH)2 = 0.0562*0.0039

[OH-] = 2*0.0562*0.0039/0.6 = 0.0007306

pOH = 3.14

pH = 10.86

4) [OH-] = (2*0.00013*0.013 + 7.4*10^-3*0.055)/(0.013+0.055) = 0.00603

pOH = 2.22

pH = 11.78

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